MATH SOLVE

4 months ago

Q:
# The attorney A, charges a fixed fee on $250 for an initial meeting and $150 per hour for all hours worked after that. The attorney B, charges $200 for one hour and $800 for five hours. For how many hours will they both cost the same amount? This is a systems of equations problem.So far I have y = cost and x = hoursFor attorney A, the equation would be y = 250 + 150xNeed help with setting up equation for attorney B

Accepted Solution

A:

Answer:For 5 hours they both will cost the same amount.Step-by-step explanation:Here, let us assume for m hours, both attorneys cost the same amount y.For Attorney A:The fixed fee = $250The per hour rate = $ 150So, the cost for m hours = m ( Cost of 1 hour ) = m ( $150) = 150 mNow, the total fees of Attorney A for m hours = Fixed fee + m hour charges y = $250 + 150 m ............... (1)For Attorney B:The fixed fee = $200The 5 hour rate = $ 800⇒ Per hour rate = $800/ 5 = $160So, the cost for m hours = m ( Cost of 1 hour ) = m ( $160) = 160 mTotal fees of Attorney B for m hours = Fixed fee + m hour charges y = $200 + 160 m .......... (2) Now comparing (1) and (2) , we get : $250 + 150 m = $200 + 160 mor, 250 - 200 = 160 m - 150 mor, 10 m = 50or, m = 50 / 10 = 5, ⇒ m = 5Hence, for 5 hours they both will cost the same amount.