A rectangular lot whose perimeter is 380 ft is fenced along three sides. An expensive fencing along the lot's length cost $ 25 per foot. An inexpensive fencing along the two side widths costs only $ 5 per foot. The total cost of the fencing along the three sides comes to $ 3625. What are the lot's dimensions?
Accepted Solution
A:
We have two widths of the same length plus one length
Let the width be [tex]w[/tex] and the length be [tex]l[/tex]
The cost is $5 per foot on the width and $25 per foot on the length Total cost = (5 × 2 × width) + (25 × length) [tex]3625 = 10w + 25l[/tex] (equation 2)
We have two variables that we need to solve, so we will need to use the simultaneous equations method (either elimination or substitution)
Since equation 1 is given [tex]190 = w + l[/tex], we can rearrange the equation to make [tex]l[/tex] the subject